...sin p, y AL e the equation to any straight line is b or dividing by o, and transposing, 50. Pitou. 2. To find the equation to a straight line in terms of the perpendicular dropped upon it from the origin, and the angles which it forms with the axes. Let p be the perpendicular,...

...; m sinw .'. tana Hence sin a = 1 + m cos w m sin w + V(l + 2m cos w + m2) 1 + m cos w + 2m cos a = Since sin a is positive, we must take the upper or...change in the meaning of the constant m. 26. To find ike equation to a straight line in terms of the perpendicular from the origin, and the inclinations...

...any straight line parallel to it will be х.У-\ - + j- = л, ab where X may have any assigned value. 26. To find the equation to a straight line in terms of the perpendicular from the origin, and the angle which this pзгрепdicular makes with the axis of x. ANALYTICAL GEOMETRY. Y Let OK=p, KOA=a....

...sometimes speak of the line represented by the equation Ax -f By + C= 0 as ' the line Ax + By -f (7.' 23. To find the equation to a straight line in terms of the intercepts which it makes on the co-ordinate axes. Let P be any point xy on a line AB which meets the...

...sometimes speak of the line represented by the equation Ax + By + C = 6 as ' the line Ax + By + G.' 23. To find the equation to a straight line in terms of the intercepts which it makes on the co-ordinate axes. Let P be any point xy on a line AB which meets the...

...square, &c. of lines through a fixed point, and know a curve on which the other end of the line lies. 25. To find the equation to a straight line in terms of the perpendicular from the origin and the angles which that perpendicular makes with the axes. Let APB be the straight line, OK the perpendicular...

...the point ( - 5, 4) we have so that a= --\5- and & = 1 The required straight line is therefore 53. To find the equation to a straight line in terms of the perpendicular let fall upon it from the origin and the angle that this .perpendicular makes with the axis of x. Let...

...5 — — find 4 - 3 3" so that a= --Y- and 6=12. The required straight line is therefore xy _ 53. To find the equation to a straight line in terms of the perpendicular let fall upon it from the origin and the angle that this perpendicular makes with t/ie axis of x. Let...

...9). Transform to polar co-ordinates a;2 — i/2 = 2ax, and to rectangular co-ordinates r=a sin B. 13. Find the equation to a straight line in terms of the perpendicular drawn to it from the origin and the inclination of that perpendicular to the axis of x. Snow how to...