The Elements of Graphic StaticsE. & F.N. Spon, 1905 - 121 páginas |
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abutment angle axle B₁ beam A B bending moments braced beam braced girder BRACED STRUCTURES bridge C₁ centre of gravity closing line combined components compressive stress concentrated load corresponding cross section D₁ dead load determined diagonals direction arrow draw equal equation exterior forces acting factor of safety fibres forces P1 funicular curve funicular polygon given directions gonals greatest Hence horizontal thrust inertia interior joint K₁ Kilos line of resistance load distribution magnitude maximum bending maximum stress metre moment of inertia neutral axis obtained ordinate P₁ parabola parallel booms parallel to CD parallelogram of forces perpendicular polygon of forces portion reaction resolved resultant roof section plane segments sides snow pressure span square foot square metre stress diagram Suppose symmetrical taking moments tangents temporary load tensile stress tension thrust H tion travelling load triangle uniform load uniformly distributed load unit of area weight wind pressure
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Página 4 - If any number of forces acting at a point are in equilibrium, lines drawn successively in the direction of the forces and proportional to their magnitudes must form a closed polygon. This polygon is termed the Polygon of Forces, and the above theorem will hold whatever is the order in which the forces are taken.
Página 112 - There are two possible ways to orient the element with respect to the axis about which the moment of inertia is to be determined.
Página 12 - A'l -12 = 82 or the shearing forces are equal to the distances of the various points of the polygon of forces from S. Accordingly in Fig. 8 A the shearing forces have been taken from the polygon of forces and used as ordinates of the segments of AF to which they correspond. [Thus the hatched figure is obtained, which is termed the "shearing force diagram...
Página 109 - E the modulus of elasticity, i the moment of inertia* about an axis passing through the centre of gravity of the section, and perpendicular to the plane in which the forces act.
Página 34 - ... independently of its derivation, and may be equally applied, whether the sides of the polygon to which it refers are in tension or pressure, provided that the polygon conforms to the conditions above described. In the latter case the funicular polygon is sometimes termed a linear arch. FIG. 19. 10. Resolution of a Force in Three Directions. — Suppose that the force P (Fig. 20) is to be resolved in three given directions, XX, YY, Z Z. If, then, the direction of P is supposed to be reversed,...
Página 101 - Combining assumptions 1 and 3, it will be seen that the stress in any fibre is proportional to its distance from the neutral...
Página 1 - O (Fig. 1) act at a point 0, then the diagonal r 0 of the completed parallelogram a 0 6 r gives the magnitude of the resultant E of those forces.
Página 45 - ... be taken in England at from 5 to 6 lbs. per square foot of the plan of the area covered. Inasmuch as the maximum wind pressure is never likely to act simultaneously with the maximum snowfall, it is probable that, in England at all events, it will be quite sufficient to provide for the former only. 2nd. Assuming the direction of the wind to be horizontal, to draw either (a) a single diagram corresponding to the normal pressure taken from the above table, or (b) to...
Página 44 - PB, the normal pressure of the wind on any plane surface in terms of P, the pressure on a plane surface perpendicular to its direction, and i the angle of inclination of that direction to the plane of the surface, the following formula was deduced by Hutton from experiment : — P.
Página 32 - ... following formula is of this kind, and gives results of considerable accuracy, when used as an interpolation formula, to obtain the weight of a girder of given dimensions from that of a similar girder of different dimensions. Let W = the total external distributed load in tons (exclusive of weight of girder). W- = weight of girder itself in tons. / = clear span in feet. d = effective depth in feet. s = average stress in tons per square inch on the gross section of the booms, at the centre.* r...