Simple Hydraulic FormulæE. & F.N. Spon, 1881 - 82 páginas |
Outras edições - Ver todos
Termos e frases comuns
10-inch main 20 feet 24 hours 667 gallons according to circumstances area in square assume a discharge bend centre of gravity channel coefficient according coefficient of discharge contour line corresponding to log cube feet cubic feet d₂ diagram Diameter in inches difference of level discharge in cube distribution pipes due to velocity equal feet per second FLOW OF WATER foot formula friction gallons in 24 gallons per minute given head due head for velocity head in feet height hydraulic inclination hydraulic mean depth logarithms loss of head Michelotti multiply Number corresponding obtained Plate VIII polygon proportional discharges quantity of water radius Rule 59 service reservoir short tubes sill siphon pipe sluice square edges square feet square root street submerged weir supply tail waters theoretical diameter theoretical velocity thin plates Total head required town velocity of approach velocity of entry wetted perimeter width yards دو وو
Passagens mais conhecidas
Página 16 - Multiply the sum of the parallel sides by the perpendicular distance between them, and half the product will be the area.
Página 16 - VI.) ; or, As 360° are to the degrees in the arc of the sector, so is the area of the circle to the area of the sector.
Página 16 - Then the sum, or difference, of these areas, according as the segment is greater or less than a semicircle, will be the area required.
Página 33 - V lj or 1 - 32, 1 - 15, and 1-0, &c. (30.) When H and d are constant, the discharge will be inversely as the square root of the length ; thus for lengths in the ratio 1, 2, 4, the discharge would be in the ratio V4, V2, and >/T, or 2-0, 1-414, and 1-0, &c.
Página 33 - When the diameter and length are constant, the discharge varies directly as the square root of the head.
Página 37 - ... for each of these spaces should be respectively as follows : — Gallons per diem. Final 200 yards 13,000 Middle 200 yards, 11,000 + 13,000 = 24,000 First 200 yards, 8,000 + 24,000 = 32,000 The calculation also assumes that the delivery of these entire quantities will take place in four hours, and that the whole of the water taken off from each length has to be passed to the end of that length. The delivery of these quantities respectively will require, according to the formula quoted, pipes...
Página 33 - If a pipe of uniform diameter has a series of branches diverging from it, so that the flow of water through it becomes less...
Página 16 - To inscribe in a circle a regular polygon of any given number of sides. Solution : Divide 360 by the number of sides, and the quotient is the number of degrees, minutes, and seconds contained in the center angle of a triangle, of which one side will make one of the sides in the polygon. For instance, draw a hexagon by this method. (See Fig.
Página 54 - Q = discharge in cubic feet per second V = velocity in feet per second...
Página 49 - It has been found that a column of water 33 or 34 feet high in a hollow tube, wherein a vacuum has been...