 | Charles Davies - 1838 - 366 páginas
...these values of r, is equal to half the parameter of the transverse axis. \ PROPOSITION XIII. THEOREM. The area of an ellipse is equal to the product of...circumference of a circle whose diameter is unity. = '4/J TV Let AB be the transverse axis of an ellipse and C the centre. On the transverse axis AB describe... | |
 | Isaac Wilber Jackson - 1845 - 116 páginas
...hyperbola, of which II' is a diameter. CHAPTER V. AREA OF THE ELLIPSE AND PARABOLA. PROPOSITION I. THEOREM. The area of an ellipse is equal to the product of its stmi-axes multiplied by the circumference of a circle whose diameter is unity. The semi-transverse... | |
 | 1850 - 124 páginas
...hyperbola, of which IT is a diameter. CHAPTER Y. AREA OF THE ELLIPSE AND PARABOLA. PROPOSITION I. THEOREM The area of an ellipse is equal to the product of...circumference of a circle whose diameter is unity. The semi-transverse and semi-conjugate axes of an ellipse being designated by a and b respectively... | |
 | 1850 - 118 páginas
...hyperbola^ of which IT is a diameter. CHAPTER V. AREA OF THE ELLIPSE AND PARABOLA. PROPOSITION I. THEOREM The area of an ellipse is equal to the product of...circumference of a circle whose diameter is unity. The semi-transverse and semi-conjugate axes of an ellipse being designated by a and b respectively... | |
 | Charles Davies - 1867 - 362 páginas
...values of r, is equal to half the parameter of the transverse axis. 138 PROPOSITION XIII. THEOREM. The area of an ellipse is equal to the product of...circumference of a circle, then, if Y designate the ordinates of the circle, and y the corresponding ordinates of the ellipse, we shall have (Prop. Ill),... | |
 | Gerardus Beekman Docharty - 1865 - 328 páginas
...circle. But the area of the circle =ir A? ; v radius = A ; TrA'B .-. area of ellipse =—r—=7rAB. Hence the area of an ellipse is equal to the product of...circumference of a circle whose diameter is unity. (106.) THE HYPERBOLA REFERRED TO ITS ASYMPTOTES. If the diagonals of the rectangle which may be described... | |
 | International Correspondence Schools - 1897 - 612 páginas
...sum of the results will be the perimeter. Art. 788. To find the exact area of an ellipse: Rule. — The area of an ellipse is equal to the product of its two diameters multiplied by . 7854. Art. 789. To find the area of any plane figure: Rule. — The area... | |
 | 1897 - 672 páginas
...+ 6.26 = 23.46 inches, or the perimeter. Ans. 789. To find the exact area of an ellipse : Rule. — The area of an ellipse is equal to the product of its two diameters multiplied by . 7854EXAMPLE. — What is the area of an ellipse whose diameters are 10... | |
 | International Correspondence Schools - 1898 - 172 páginas
...- =.. a.\. b nM r "/ . TX 64 — 3 D. Then, C ="(« + *. To find the area of an ellipse: Rule. — The area of an ellipse is equal to the product of its two diameters multiplied by . 7854. Art. 1 44. THE PRISM AND CYLINDER. To find the area of the convex... | |
 | 1900 - 728 páginas
...+ 5.26 = 23.46 inches, or the perimeter. Ans. 789. To find the exact area of an ellipse : Rule. — The area of an ellipse is equal to the product of its two diameters multiplied by . 7854. EXAMPLE. — What is the area of an ellipse whose diameters are... | |
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I —e cos v Scholium 6. It should be remarked, that the common numerator in these values of r, is equal to half the parameter of the transverse axis. 