Elementary Theory and Calculation of Iron Bridges and RoofsE. & F.N. Spon, 1879 - 395 páginas |
Conteúdo
| 1 | |
| 17 | |
| 26 | |
| 36 | |
| 38 | |
| 39 | |
| 40 | |
| 44 | |
| 234 | |
| 241 | |
| 264 | |
| 266 | |
| 268 | |
| 282 | |
| 287 | |
| 290 | |
| 52 | |
| 59 | |
| 72 | |
| 87 | |
| 93 | |
| 105 | |
| 111 | |
| 126 | |
| 147 | |
| 157 | |
| 164 | |
| 178 | |
| 180 | |
| 188 | |
| 195 | |
| 201 | |
| 213 | |
| 227 | |
| 294 | |
| 301 | |
| 305 | |
| 309 | |
| 310 | |
| 321 | |
| 340 | |
| 347 | |
| 350 | |
| 353 | |
| 355 | |
| 359 | |
| 362 | |
| 366 | |
| 367 | |
| 373 | |
| 389 | |
Outras edições - Ver todos
Elementary Theory and Calculation of Iron Bridges and Roofs August Ritter Visualização completa - 1879 |
Elementary Theory and Calculation of Iron Bridges and Roofs August Ritter Visualização completa - 1879 |
Elementary Theory and Calculation of Iron Bridges and Roofs August Ritter Visualização completa - 1879 |
Termos e frases comuns
abutments axis beam bending braced arches bridge is fully calculations central span centre chains considered curve dead load deflection equal equation of moments equilibrium evidently F₁ find the stress following equations fully loaded given in Fig gonals greatest stress h₁ h₂ half Hence hinge hinge-reaction horizontal bars horizontal reactions kilos lattice girders live load load produces load Q loading boundary lower boom lower joints M₁ maximum method of moments millimetre minimum stress moment of inertia moving load negative obtained parabolic girders permanent load pier points of support positive resultant ribs ring rods roof S₁ section line shown in Fig stress produced structure substituting suspension bridge taking moments temperature tons truss U₁ U₂ uniformly distributed unit of length unloaded upper joints V₁ V₂ vertical forces vertical reaction weight X₁ X₂ Y₁ Y₂ Z₁ Z₂ max
Passagens mais conhecidas
Página 317 - CC j have undergone during the flexure of the beam A B. surface CC^ and by Hooke's law the alterations of length are also proportional to the stresses, hence the stress in any fibre is proportional to its distance from the neutral surface. Let s be the stress of a fibre at a unit of distance from the neutral axis N NI , then the stress in a fibre distant y from the neutral axis is s . y.
Página 346 - In a beam supported at both ends and loaded in the centre, the deflection curve will evidently be a circle.
Página 4 - ... (in its more general form the law of statical moments), and can therefore. be easily understood by those who are acquainted but with the very elements of mechanics. In fact only the last equation, that of statical moments, need be used, for if to obtain the stress in one bar moments are taken round the point of intersection of the other two bars, an equation will be arrived at containing only one unknown, the stress required, for evidently the moments of the stresses in the other two bars vanish....
Página 307 - If the mass of every particle of a material system be multiplied by the square of its distance from a straight line, the sum of the products so formed is called the moment of inertia of the system about that line.
Página 352 - For this reason^ girders in which the verticals are in compression and the diagonals in tension, are generally to be preferred to other forms.
Página 331 - Equation 68, viz. is therefore perfectly general and is applicable to the case of any beam under bending stress. Now, it is shown in works on geometry that for any curve referred to rectangular axes, p=± dx...