Great Books of the Western World, Band 11Robert Maynard Hutchins Encyclopædia Britannica, 1952 |
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Seite 80
... equiangular . But it was also proved equilateral ; and it has been inscribed in the circle ABCDEF . Therefore in the given circle an equilateral and equiangular hexagon has been inscribed . Q. E. F. PORISM . From this it is manifest ...
... equiangular . But it was also proved equilateral ; and it has been inscribed in the circle ABCDEF . Therefore in the given circle an equilateral and equiangular hexagon has been inscribed . Q. E. F. PORISM . From this it is manifest ...
Seite 104
... equiangular and will have those angles equal which the corresponding sides subtend . Let ABC , DEF be two triangles having one angle BAC equal to one angle EDF and the sides about the equal angles proportional , so that , as BA is to AC ...
... equiangular and will have those angles equal which the corresponding sides subtend . Let ABC , DEF be two triangles having one angle BAC equal to one angle EDF and the sides about the equal angles proportional , so that , as BA is to AC ...
Seite 374
... equiangular . For in the equilateral pentagon ABCDE let , first , three angles taken in or- der , those at A , B , C , be equal to one another ; I say that the pentagon ABCDE is equiangular . For let AC , BE , FD be joined . Now , since ...
... equiangular . For in the equilateral pentagon ABCDE let , first , three angles taken in or- der , those at A , B , C , be equal to one another ; I say that the pentagon ABCDE is equiangular . For let AC , BE , FD be joined . Now , since ...
Inhalt
DEFINITIONS POSTULATES | 1 |
DEFINITIONS | 30 |
DEFINITIONS | 41 |
Urheberrecht | |
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angle ABC angle BAC apotome axis base BC is equal bisected centre of gravity circle ABCD circumference commensurable in length commensurable in square cone continued proportion cube cylinder diameter drawn parallel ellipse equal angles equiangular equimultiples Eucl frustum given straight line gnomon greater hyperbola incommensurable inscribed less Let ABC let the straight magnitudes medial straight line meet multiplying opposite sections parabola parallelogram perpendicular plane plane of reference point of contact polygon prime prism produced PROPOSITION 14 proved pyramid Q. E. D. PROPOSITION ratio rational straight line rect rectangle contained remaining angle right angles segment side similar Similarly solid sphere square number squares on AC straight line AB straight line AC straight lines commensurable surface tangent trgl triangle ABC twice the rectangle vertex